![If tan (picottheta) = cot (pitantheta) , then show that tantheta = 14 [2n + 1±√(4n^2 + 4n - 15) ] , where n>1 or n< - 2 .](https://haygot.s3.amazonaws.com/questions/1593940_1730964_ans_19d044251d674951aa1541164d035616.jpg "If tan (picottheta) = cot (pitantheta) , then show that tantheta = 14 [2n + 1±√(4n^2 + 4n - 15) ] , where n>1 or n< - 2 .")
If tan (picottheta) = cot (pitantheta) , then show that tantheta = 14 [2n + 1±√(4n^2 + 4n - 15) ] , where n>1 or n< - 2 .
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![Solved] What is cotangent of PI over 2 (cot PI over 2 radians) – LUNLUN.COM](https://lunlun.com/wp-content/uploads/2020/08/Solved-What-is-cotangent-of-PI-over-2-cot-PI-over-2-radians.png "Solved] What is cotangent of PI over 2 (cot PI over 2 radians) – LUNLUN.COM")
Solved] What is cotangent of PI over 2 (cot PI over 2 radians) – LUNLUN.COM
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&line2=\mathrm{Solution:\:}0 "cot(pi/2) - Symbolab")
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)&line2=\mathrm{Solution:\:}0 "What is the derivative of cot(pi/2) ? - Symbolab")
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![calculus - How can I evaluate $\lim_{n\to\infty}\Big[ \cot(\pi\sqrt{100n^2+n+1}\Big]$ - Mathematics Stack Exchange](https://i.stack.imgur.com/jX1Av.jpg "calculus - How can I evaluate $\lim_{n\to\infty}\Big[ \cot(\pi\sqrt{100n^2+n+1}\Big]$ - Mathematics Stack Exchange")
calculus - How can I evaluate $\lim_{n\to\infty}\Big[ \cot(\pi\sqrt{100n^2+n+1}\Big]$ - Mathematics Stack Exchange
-\cot(\frac{%CF%80}{6})&line2=\mathrm{Solution:\:}-\sqrt{3} "cot((3pi)/2)-cot(pi/6) - Symbolab")
cot((3pi)/2)-cot(pi/6) - Symbolab
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